Encuentre el siguiente limite
L i m x → ∞ 2 x + 1 x 2 + 3 L i m x → ∞ 2 x x + 1 x x 2 x 2 + 3 x 2 = L i m x → ∞ ( 2 ∗ 1 ) − 0 1 + 0 = 2 1 = L i m x → ∞ 2 {\displaystyle {Lim}_{x\rightarrow \infty }{\frac {2x+1}{\sqrt {x^{2}+3}}}{Lim}_{x\rightarrow \infty }{\frac {{\frac {2x}{x}}+{\frac {1}{x}}}{\sqrt {{\frac {x^{2}}{x^{2}}}+{\frac {3}{x^{2}}}}}}={Lim}_{x\rightarrow \infty }{\frac {(2*1)-0}{\sqrt {1+0}}}={\frac {2}{1}}=Lim_{x\rightarrow \infty }2}
