${\displaystyle {\begin{aligned}&86,6-120{\sqrt {1-{\frac {\alpha }{\pi }}+{\frac {\operatorname {sen} (2\alpha )}{2\pi }}}}=0\\&\alpha =1,54\ \mathrm {rad} =88,1^{\circ }\end{aligned}}}$

In your article, replace the image with:

<math>\begin{align} & 86,6 - 120 \sqrt{1 - \frac{\alpha}{\pi} + \frac{\operatorname{sen}(2\alpha)}{2 \pi} } = 0 \\ & \alpha = 1,54\  \mathrm{rad} = 88,1^{\circ} \end{align}</math>

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